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11x^2-22x+8.5=0
a = 11; b = -22; c = +8.5;
Δ = b2-4ac
Δ = -222-4·11·8.5
Δ = 110
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-\sqrt{110}}{2*11}=\frac{22-\sqrt{110}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+\sqrt{110}}{2*11}=\frac{22+\sqrt{110}}{22} $
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